2(x-3)(x+2)=4+2x^2

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Solution for 2(x-3)(x+2)=4+2x^2 equation: 



2(x-3)(x+2)=4+2x^2

We move all terms to the left:

2(x-3)(x+2)-(4+2x^2)=0

We get rid of parentheses

-2x^2+2(x-3)(x+2)-4=0

We multiply parentheses ..

-2x^2+2(+x^2+2x-3x-6)-4=0

We multiply parentheses

-2x^2+2x^2+4x-6x-12-4=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8

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